Answer
$x= 4$.
Work Step by Step
Given
\begin{equation}
\begin{aligned}
& \sqrt{x}+3=5 \\
& {[-1,6,1] \text { by }[-1,6,1]}
\end{aligned}
\end{equation}
Let
\begin{equation}
\begin{aligned}
f(x)&= \sqrt{x}+3\\
g(x)&=5\\
\end{aligned}
\end{equation}
A plot of the two function is shown in the figure. We see that the point of intersection between the graphs of the functions is at $(x,y) = (4,5)$. This means that the solution is $x= 4$. Let's check.
\begin{equation}
\begin{aligned}
\sqrt{4}+3& \stackrel{?}{=}5 \\
2+3& \stackrel{?}{=}5 \\
5&= 5\checkmark
\end{aligned}
\end{equation}
