Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 561: 68

Answer

$x= 7$

Work Step by Step

A plot of the two function is shown in the figure. We see that the point of intersection between the graphs of the function is at $(x,y) = (7,4)$. This means that the solution is $x= 7$. Let's check. \begin{equation} \begin{aligned} \sqrt{2 \cdot 7+2}& \stackrel{?}{=}\sqrt{3 \cdot 7-5} \\ \sqrt{14+2}& \stackrel{?}{=}\sqrt{21-5} \\ \sqrt{16}& \stackrel{?}{=}\sqrt{16} \\ 4&= 4\checkmark \end{aligned} \end{equation}
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