Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 559: 9


$x=3$ or $x=0$

Work Step by Step

Square both sides of the equation to obtain: $5x+1=(x+1)^2$ Use the rule $(a+b)^2 = a62 + 2ab+b^2$ where $a=x$ and $b=1$ to obtain: $\\5x+1=x^2+2x+1$ Move all terms to the right side of the equation. Note that when a term is moved to the other side of the equation, its sign changes to its opposite. $0=x^2+2x+1-5x-1 \\0=x^2-3x$ Factor the binomial to obtain: $0=x(x-3)$ Equate each factor to zero then solve each equation to obtain: $x = 0 \text{ or } x -3 = 0 \\x = 0 \text{ or } x = 3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.