## Intermediate Algebra for College Students (7th Edition)

$x=35$
Add 4 on both sides of the equation to obtain: $\sqrt[3]{2x-6}=4$ RECALL: For any real number $a$, $(\sqrt[3]{a})^3=a$ Cube both sides then use the rule above to simplify: $(\sqrt[3]{2x-6})^3 = 4^3 \\2x-6=64$ Add 6 on both sides to obtain: $2x = 64+6 \\2x=70$ Divide 2 on both sides to obtain: $x=35$