Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Concept and Vocabulary Check - Page 559: 6



Work Step by Step

Substitute $4$ to $x$ in the given equation to obtain: $\sqrt{5(4) + 16}=4+2 \\\sqrt{20+16} = 6 \\\sqrt{36} = 6 \\6=6$ $4$ satisfies the equation so it is a solution of the equation. Thus, the given statement is true.
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