Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Concept and Vocabulary Check - Page 559: 5

Answer

$2x+3$; $8$

Work Step by Step

RECALL: $(a^{\frac{1}{3}})^3=a$ Cube both sides of the equation to obtain: $\left((2x+3)^{\frac{1}{3}}\right)^3=2^3 \\\left((2x+3)^{\frac{1}{3}}\right)^3=8 $ Use the rule above to obtain: $2x+3=8$ Thus, the missing expressions in the given statements are $2x+3$ and $8$, respectively
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