Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 541: 107

Answer

$x^2y^3a^5b\sqrt { b}$.

Work Step by Step

The given expression is $=\frac{6\sqrt {49xy}\sqrt {ab^2}}{7\sqrt {36x^{-3}y^{-5}}\sqrt{a^{-9}b^{-1}}}$ Multiply the radicands and retain the common index. $=\frac{6\sqrt {49xy\cdot ab^2}}{7\sqrt {36x^{-3}y^{-5}\cdot a^{-9}b^{-1}}}$ Simplify. $=\frac{6\sqrt {7^2xy\cdot ab^2}}{7\sqrt {6^2x^{-3}y^{-5}\cdot a^{-9}b^{-1}}}$ $=\frac{6\cdot 7 \sqrt {xy\cdot ab^2}}{7\cdot 6 \sqrt {x^{-3}y^{-5}\cdot a^{-9}b^{-1}}}$ Cancel common terms. $=\frac{ \sqrt {xy\cdot ab^2}}{ \sqrt {x^{-3}y^{-5}\cdot a^{-9}b^{-1}}}$ Divide the radicands and retain the common index. $=\sqrt {\frac{ xy\cdot ab^2}{x^{-3}y^{-5}\cdot a^{-9}b^{-1}}}$ Divide factors in the radicand. Subtract exponents on common bases. $=\sqrt { x^{1+3}y^{1+5}a^{1+9}b^{2+1}}$ Simplify. $=\sqrt { x^{4}y^{6}a^{10}b^{3}}$ $=x^2y^3a^5b\sqrt { b}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.