Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.4 - Adding, Subtracting, and Dividing Radical Expressions - Exercise Set - Page 541: 104

Answer

False.

Work Step by Step

Solve the left hand side. $=\frac{\sqrt{-8}}{\sqrt2}$ Divide the radicands and retain the common index. $=\sqrt{\frac{-8}{2}}$ Simplify. $=\sqrt{-4}$ $=\sqrt{-1\cdot 2^2}$ $=2\sqrt{-1}$ The last term is not correct. Hence, the statement is false.
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