Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Concept and Vocabulary Check: 4

Answer

$f(x) = |x+1|\sqrt{5}$

Work Step by Step

RECALL: (i) $\sqrt{a^2} = a$ when $a \ge 0$ (ii) $\sqrt{a^2} = |a|$ when $a \lt 0$ $x$ can be any real number. This means that when $x \lt -1$, the value of $x+1$ is negative. Thus, to simplify $f(x)=\sqrt{5(x+1)^2}$, rule (ii) above must be used. Therefore, $f(x) = |x+1|\sqrt{5}$
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