## Intermediate Algebra for College Students (7th Edition)

The missing expressions are: $8$; $5$; $2\sqrt[3]{5}$
RECALL: $\sqrt[3]{ab} = \sqrt[3]{a} \cdot \sqrt[3]{b}$ Use the rule above to obtain: $=\sqrt[3]{\underline{8}} \cdot \sqrt[3]{\underline{5}} \\=\sqrt[3]{2^3} \cdot \sqrt[3]{5}$ Use the rule $\sqrt[3]{a^3}=a$ to obtain: $=2 \cdot \sqrt[3]{5} \\=2\sqrt[3]{5}$