Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Cumulative Review Exercises - Page 579: 19

Answer

The amount at $7\%=\$1500$. The amount at $9\%=\$4500$.

Work Step by Step

Step 1:- Assume unknown quantities as variables. Let the amount at $7\%$ $=x$. Let the amount at $9\%$ $=y$. Step 2:- Write system of equations. The given values are Total amount $= \$6000$ Total interest $= \$510$ Or we can write. $\Rightarrow x+y=6000$ ...... (1) $\Rightarrow 0.07x+0.09y=510$ ...... (2) Step 3:- Solve the system of equations. Multiply equation (1) by $-0.07$. $\Rightarrow -0.07x-0.07y=-420$ ...... (3) Add equation (2) and (3). $\Rightarrow 0.07x+0.09y-0.07x-0.07y=510-420$ Simplify. $\Rightarrow 0.02y=90$ Divide both sides by $0.02$. $\Rightarrow \frac{0.02y}{0.02}=\frac{90}{0.02}$ Simplify. $\Rightarrow y=4500$ Plug the value of $y$ into equation (1). $\Rightarrow x+4500=6000$ Isolate $x$. $\Rightarrow x=6000-4500$ Simplify. $\Rightarrow x=1500$. Step 4:- Check the answers. Substitute the values of $x$ and $y$ into equation (2). $\Rightarrow 0.07(1500)+0.09(4500)=510$ $\Rightarrow 105+405=510$ $\Rightarrow 510=510$. True.
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