Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 476: 32


$15 $ mph

Work Step by Step

distance = (rate)$\times$(time) $\Rightarrow$ time = $\displaystyle \frac{\text{distance}}{\text{rate}}$ Let x be the rate of the bicyclist in calm air. We are given: $\displaystyle \frac{75}{x+10}=\frac{15}{x-10} \qquad$ ... $/\times(x+10)(x-10)$ $75(x-10)=15(x+10)$ $ 75x-750=15x+150\qquad$ ... add $750- 15x$ $ 60x=900\qquad$ ...$ /\div 60$ $x=15 $mph rate of the bicyclist in calm air = $15 $ mph
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