Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 476: 31


$500 $ mph

Work Step by Step

distance = (rate)$\times$(time) $\Rightarrow$ time = $\displaystyle \frac{\text{distance}}{\text{rate}}$ Let x be the rate of the airplane in calm air. We are given: $\displaystyle \frac{2400}{x+100}=\frac{1600}{x-100} \qquad$ ... $/\times(x+100)(x-100)$ $2400(x-100)=1600(x+100)$ $ 2400x-240,000=1600x+160,000\qquad$ ... add $240000- 1600x$ $ 8000x=400,000\qquad$ ...$ /\div 8000$ $x=500 $mph rate of the airplane in calm air = $500 $mph
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.