Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Section 6.7 - Formulas and Applications of Rational Equations - Exercise Set - Page 476: 31

Answer

$500 $ mph

Work Step by Step

distance = (rate)$\times$(time) $\Rightarrow$ time = $\displaystyle \frac{\text{distance}}{\text{rate}}$ Let x be the rate of the airplane in calm air. We are given: $\displaystyle \frac{2400}{x+100}=\frac{1600}{x-100} \qquad$ ... $/\times(x+100)(x-100)$ $2400(x-100)=1600(x+100)$ $ 2400x-240,000=1600x+160,000\qquad$ ... add $240000- 1600x$ $ 8000x=400,000\qquad$ ...$ /\div 8000$ $x=500 $mph rate of the airplane in calm air = $500 $mph
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