Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Cumulative Review Exercises - Page 500: 12

Answer

$ x^2+4x+4-9y^2$.

Work Step by Step

We notice that the given expression contains two factors which can be written as $A+B$ and $A-B$, where $A=x+2$ and $B=3y$.. Use the special formula $(A+B)(A-B)=A^2-B^2$. $\Rightarrow [(x+2)+3y][(x+2)-3y]=(x+2)^2-(3y)^2$ Use the special formula $(A+B)^2=A^2+2AB+B^2$ to expand $(x+2)^2$, where $A=x$ and $B=2$. $\Rightarrow = x^2+4x+4-9y^2$.
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