Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 393: 81

Answer

Length: $12$ feet Width: $5$ feet

Work Step by Step

The dimensions of the closet's base are: $$\begin{align*} &\text{Length:}& 2x+2\\ &\text{Width:}& x.\\ \end{align*}$$ We use the Pythagorean theorem to calculate $x$: $$\begin{align*} x^2+(2x+2)^2&=13^2\quad&&\text{Apply the Pythagorean theorem.}\\ x^2+4x^2+8x+4-169&=0\quad&&\text{Subtract }169\text{ from each side.}\\ 5x^2+8x-165&=0\quad&&\text{Simplify.}\\ (x-5)(5x+33)&=0\quad&&\text{Factor.}\\ x-5=0&\text{ or }5x+33=0\quad&&\text{Set each factor to }0.\\ x=5&\text{ or }x=-\dfrac{33}{5}\quad&&\text{Solve for }x. \end{align*}$$ As $x$ is a dimension, it must be positive, so the only solution is $x=5$. Calculate the dimensions of the triangle: $$\begin{align*} &\text{Length:}& 2x+2=2(5)+2=12\\ &\text{Width:}& x=5. \end{align*}$$
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