Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 393: 79

Answer

Length: $10$ inches Width: $10$ inches

Work Step by Step

The dimensions of the box are: $$\begin{align*} &\text{Length:}& x\\ &\text{Width:}& x\\ &\text{Height:}& 2. \end{align*}$$ We are given that its volume is $V=200$. We solve the equation $V=200$ for $x$: $$\begin{align*} x\cdot x\cdot 2&=200\quad&&\text{Write the given equation.}\\ x^2&=100\quad&&\text{Divide each side by }2.\\ x&=\pm 10\quad&&\text{Take the square root.} \end{align*}$$ As $x$ is a dimension, it must be positive, so the only solution is $x=10$. Calculate the dimensions of the box: $$\begin{align*} &\text{Length:}& x=10\\ &\text{Width:}& x=10\\ &\text{Height:}& 2. \end{align*}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.