Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.7 - Polynomial Equations and Their Applications - Exercise Set - Page 391: 59



Work Step by Step

As per given question: $(x-1)(x+4)=24$ This can be written as: $x^2+4x-x-4-24=0$ or, $x^2+3x-28=0$ Need to use factorization to solve the quadratic equation . $x^2+7x-4x-28=0$ or, $(x+7)(x-4)=0$ This implies $x+7=0$ and $x-4=0$ Hence, $x=-7,4$
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