Answer
$(x+y)(3b+4)(3b-4)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $9b^2x+9b^2y-16x-16y=9b^2(x+y)-16(x+y)=(x+y)(9b^2-16)=(x+y)((3b)^2-4^2)=(x+y)(3b+4)(3b-4)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 374: 145
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