Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 374: 138

Answer

$16$.

Work Step by Step

The given expression is $kx^2+8xy+y^2$ Use the algebraic expression. $a^2+2ab+b^2=(a+b)^2$. Factor the middle term of the given expression as shown below. $8xy = 2(4x)(y)$ Compare the above term with the algebraic expression. $2ab=2(4x)(y)$ We have $a=4x$ and $b=y$. Therefore $kx^2=a^2$. Plug all values. $kx^2=(4x)^2$. Simplify. $kx^2=16x^2$. Divide both side by $x^2$. $k=16$.
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