Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 401: 97

Answer

$3,-3,-5$

Work Step by Step

Given: $x^3+5x^2=9x+45$ This gives $x^3+5x^2-9x-45=0$ or, $x^2(x+5)-9(x+5)=0$ or, $(x^2-9)(x+5)=0$ Thus, $(x-3)(x+3)(x+5)=0$ Hence, $x=3,-3,-5$
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