Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Review Exercises - Page 401: 95

Answer

$\{-8,7\}$.

Work Step by Step

$x(x-2)+3(x-2)=50$ Use the distributive property. $x^2-2x+3x-6=50$ Add like terms. $x^2+x-6=50$ Subtract $50$ from both sides. $x^2+x-6-50=50-50$ Add like terms. $x^2+x-56=0$ Rewrite the middle term $x$ as $8x-7x$. $x^2+8x-7x-56=0$ Group terms. $(x^2+8x)+(-7x-56)=0$ Factor each term. $x(x+8)-7(x+8)=0$ Factor out $(x+8)$. $(x+8)(x-7)=0$ Set each factor equal to zero. $x+8=0$ or $x-7=0$ Isolate $x$. $x=-8$ or $x=7$. The solution set is $\{-8,7\}$.
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