Answer
$x\lt\frac{bc-b}{a}$
Work Step by Step
$\frac{ax+b}{c}\gt b$ If I multiply both sides by $c$, the sign changes because $c$ is negative. Thus: $ax+b\lt bc\\ax\lt bc-b$.
If I divide both sides by $a$, the sign doesn't change because $a$ is positive.
Thus $x\lt\frac{bc-b}{a}$
