## Intermediate Algebra for College Students (7th Edition)

$x\lt\frac{bc-b}{a}$
$\frac{ax+b}{c}\gt b$ If I multiply both sides by $c$, the sign changes because $c$ is negative. Thus: $ax+b\lt bc\\ax\lt bc-b$. If I divide both sides by $a$, the sign doesn't change because $a$ is positive. Thus $x\lt\frac{bc-b}{a}$