Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.1 - Solving Linear Inequalities - Exercise Set - Page 262: 42



Work Step by Step

$\frac{ax+b}{c}\gt b$ If I multiply both sides by $c$, the sign changes because $c$ is negative. Thus: $ax+b\lt bc\\ax\lt bc-b$. If I divide both sides by $a$, the sign doesn't change because $a$ is positive. Thus $x\lt\frac{bc-b}{a}$
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