Answer
$x\geq\frac{-19}{6}$
Work Step by Step
$\frac{4x-3}{6}+2\geq\frac{2x-1}{12}\\2(4x-3)+24\geq2x-1\\8x-6+24\geq2x-1\\6x+18\geq-1\\6x\geq-19\\x\geq\frac{-19}{6}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 4 - Section 4.1 - Solving Linear Inequalities - Exercise Set - Page 262: 20
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
