Answer
$\frac{-2}{3}\frac{y^{7}}{x^{5}}$
Work Step by Step
$\frac{-10x^2y^4}{15x^7y^{-3}}\\=\frac{-2}{3}x^{2-7}y^{4+3}\\=\frac{-2}{3}x^{-5}y^{7}\\=\frac{-2}{3}\frac{y^{7}}{x^{5}}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 4 - Cumulative Review Exercises - Page 311: 3
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