Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Test - Page 250: 2

Answer

$(6,-5)$

Work Step by Step

We have two equations such as: $5x+4y=10$ and $3x+5y=-7$ From the first equation, we have $y=\dfrac{10-5x}{4}$ Plug the above value of $y$ in the second equation. $3x+5(\dfrac{10-5x}{4})=-7$ or, $-13x=-28-50$ or, $x=6$ and $y=\dfrac{10-5(6)}{4}=-5$ Hence, $(x,y)=(6,-5)$
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