Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 215: 9



Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $-6x-4y+6z=4$ and $6x-15y+6z=-6$ This gives, $-19y+12z=-2$ Now, $-4x+10y-4z=4$ and $-20x+18z=16$ This gives $y=2$ Now, $-19(2)+12z=-2$ or, $z=3$ Also, $-6x-4y+6z=4$ $-6x-4(2)+6(3)=4$ or, $x=1$ Hence, the desired result is $(1,2,3)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.