Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.3 - Systems of Linear Equations in Three Variables - Exercise Set - Page 215: 10



Work Step by Step

To solve the given problem we will have to plug the simplest equation into the other equation and then solve for the other variable. $-6x-9y-21z=-39$ and $6x+4y-10z=-44$ This gives, $-5y-31z=-83$ Now, $-55y-341z=-913$ and $55y+80z=130$ This gives $y=-2$ Now, $-19(2)+12z=-2$ or, $z=3$ Also, $-6x-9y-21z=-39$ $-6x-9(-2)-21(3)=-39$ or, $x=-1$ Hence, the desired result is $(-1,-2,-3)$
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