Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 205: 20

$x=8,y=24$

As per the statement: $x+y=32$ and $0.16x+0.28y=(0.25)(32)$ After plugging the variable $x$ form the first equation in the second equation, we get $0.16(32-y)+0.28y=(0.25)(32) \implies 0.12y=2.88$ or, $y=24$ Now, $x+24=32 \implies x=8$ Thus, $x=8,y=24$