Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 3 - Section 3.2 - Problem Solving and Business Applications Using Systems of Equations - Exercise Set - Page 205: 14

Answer

The investment in stocks $=\$5,000$. The investment in the bonds $=\$6,000$

Work Step by Step

Let the investment in stocks is $x$. and the investment in the bonds is $y$. The total investment is. $\Rightarrow x+y=11,000$ ...... (1) Annual interest from stocks $=5\%$ of $x$. $=0.05x$. Annual interest from bonds $=8\%$ of $y$. $=0.08y$. The total interest is. $\Rightarrow 0.05x+0.08y = 730$ ...... (2) Multiply equation (1) by $-0.05$. $\Rightarrow -0.05\cdot (x+y)=-0.05\cdot 11,000$ Apply distributive property. $\Rightarrow -0.05x-0.05y=-550$ ...... (3) Add equation (2) and (3). $\Rightarrow 0.05x+0.08y -0.05x-0.05y= 730-550$ Add like terms. $\Rightarrow 0.03y =180$ Divide both sides by $0.03$. $\Rightarrow \frac{0.03y}{0.03} =\frac{180}{0.03}$ Simplify. $\Rightarrow y =6,000$ Plug the value of $y$ into equation (1). $\Rightarrow x+6,000=11,000$ Subtract $6,000$ from both sides. $\Rightarrow x+6,000-6,000=11,000-6,000$ Simplify. $\Rightarrow x=5,000$
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