## Intermediate Algebra for College Students (7th Edition)

(a.) Slope-intercept form $y=\frac{-5}{3}x+5$. (b.) Slope $m=\frac{-5}{3}$ and $y−$ intercept is $b=5$. (c.) The graph is shown below.
(a) The standard slope-intercept form is $y=mx+c$. Where, $m=$ slope and $c=y−$intercept. The given equation is $5x+3y=15$. Isolate $y$. $y=\frac{-5}{3}x+5$. (b.) The slope of the equation is $m=\frac{-5}{3}$. and the $y−$ intercept is $b=5$. (c.) The first point is $(0,5)$, because $b=5$. For the second point use slope. slope $=\frac{-5}{3}=\frac{Rise}{Run}$. The second point is $(0+3,5-5)=(3,0)$. By using these two point draw a straight line.