Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.4 - Linear Functions and Slope - Exercise Set - Page 152: 40


slope = 0 y-intercept = $-\frac{1}{3}$

Work Step by Step

RECALL: (i) The graph of the equation $y=k$ is a horizontal line, where $k$ = the y-intercept. (ii) A horizontal line has a slope of zero. This means that the graph of given equation is a horizontal line with a slope of zero and a y-intercept of $-\frac{1}{3}$. Thus, the given line has: slope = $0$ y-intercept = $-\frac{1}{3}$ To graph this equation, perform the following steps: (1) All points on the line $y=-\frac{1}{3}$ have a y-value of $-\frac{1}{3}$. Plot the points $(-3, -\frac{1}{3})$, $(0, -\frac{1}{3})$, and $(3, -\frac{1}{3})$ (2) Plot each ordered pair, and then connect the points using a line. (Refer to the attached image in the answer part above.)
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