Intermediate Algebra for College Students (7th Edition)

$-3$
Points on the graph: $(-2.5,2)$, so $f(-2.5)=2,$ $(1.9,-2)$, so $f(1.9)=-2,$ $(-\pi,3),$so $f(-\pi)=3,$ $(-3,2),$so $f(-3)=2,$ $(1,-2),$so $f(1)=-2$ $(\pi,-4),$so $f(\pi)=-4.$ So, we calculate $\sqrt{2-(-2)}-(3)^{2}+2\div(-2)\times(-4)=2-9+4=-3$