Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.2 - Graphs of Functions - Exercise Set - Page 125: 68

Answer

$-18$

Work Step by Step

Points on the graph: $(-1.5,1)$, so $f(-1.5)=1,$ $(-0.9,0)$, so $f(-0.9)=0,$ $(\pi,-4), $so $f(\pi)=-4,$ $(-3,2), $so $f(-3)=2,$ $(1,-2), $so $f(1)=-2$ $(-\pi,3), $so $f(-\pi)=3.$ So, we calculate $\sqrt{1+0}-(-4)^{2}+2\div(-2)\times 3=1-16-3=-18$
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