Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set: 53

Answer

$\frac{y^{10}}{9x^{4}}$

Work Step by Step

Use powers-to power and quotient rules. $=(\frac{3x^{2}y^{-2}}{y^{3}})^{-2}$ $=\frac{(3x^{2}y^{-2})^{-2}}{(y^{3})^{-2}}$ $=\frac{3^{-2}x^{2\times-2}y^{-2\times-2}}{y^{3\times-2}}$ $=\frac{x^{-4}y^{4}}{9y^{-6}}$ $=\frac{y^{10}}{9x^{4}}$
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