Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 2 - Section 2.1 - Introduction to Functions - Exercise Set - Page 114: 52



Work Step by Step

$=24\div4[2-(5-2)]^{2}-6$ $=24\div4[2-(3)]^{2}-6$ $=24\div4[-1]^{2}-6$ $=24\div4-6$ $=6-6$ $=0$
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