Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.3 - Geometric Sequences and Series - Exercise Set - Page 855: 73

Answer

$\$30,000$ more will be from the lump-sum investment than from the annuity.

Work Step by Step

First condition Lump-Sum deposit. $P=\$30,000$ Rate of interest compounded annually $r=5\%=0.05$. Time $t=20$ years. The compounded interest formula is $A=P(1+r)^t$. Substitute all values into the formula. $A=30,000(1+0.05)^{20}$ $A=79598.9311543$ Round to the nearest dollar. $A=\$79599$ Second condition Periodic deposits. First year $=\$1500$ Second year $=\$1500(1.05)$ Third year $=\$1500(1.05)^2$ and so on. This is the geometric sequence. The sum of the all $20$ years deposits is $S_{20}=\frac{1,500(1-(1.05)^{20})}{1-1.05}$ Simplify. $S_{20}=\$49598.9311543$ Round to the nearest dollar. $A=\$49599$. The difference of both condition is $\$79599-\$49599=\$30,000$.
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