Answer
$2435$
Work Step by Step
For a geometric sequence, $a_n=a_1r^{n-1}$
Thus, $ a_{10}=(-5)(-2)^{10-1}=2560$
For an arithmetic sequence, we have $b_n=b_1+(n-1)d$
Thus, $b_{10}=10+(10-1)(-15)=-125$
Therefore, $a_{10}+b_{10}=2560+(-125)=2435$
