Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 841: 71

Answer

$2869$ seats

Work Step by Step

Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Our aim is to determine a formula for the general term of the arithmetic sequence $a_n$. Such as: $a_n=a_1+(n-1)d$ For $n=38$ $s_{38}=19(a_1+a_{38})$ ...(1) Now, $a_n=a_1+(n-1)d$ $\implies a_{38}=a_1+(37)(3)=20+(37)(3)=131$ From equation (1), we have $s_{38}=19(20+131)=2869$
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