Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 11 - Section 11.2 - Arithmetic Sequences - Exercise Set - Page 841: 68

Answer

$442500$

Work Step by Step

Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Here $n=10$ Thus, $S_{10}=\dfrac{10}{2}5(a_1+a_{10})$ ...(1) $a_1=33000$ and $a_{10}=33000+(9)(2500)=55500$ From equation (1), we have $S_{10}=\dfrac{10}{2}5(a_1+a_{10})=5(33000+55500)=442500$
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