## Intermediate Algebra for College Students (7th Edition)

$442500$
Sum of the an arithmetic series can be calculated by using formula $S_n=\dfrac{n}{2}(2a_1+(n-1)d)$ Here $n=10$ Thus, $S_{10}=\dfrac{10}{2}5(a_1+a_{10})$ ...(1) $a_1=33000$ and $a_{10}=33000+(9)(2500)=55500$ From equation (1), we have $S_{10}=\dfrac{10}{2}5(a_1+a_{10})=5(33000+55500)=442500$