Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.5 - Systems of Nonlinear Equations in Two Variables - Exercise Set - Page 813: 83



Work Step by Step

Simplify.$(3x-2)(2x^2-4x+3)$ Now, $=3x(2x^2-4x+3)-2(2x^2-4x+3)$ $=6x^3-12x^2+9x-4x^2+8x-6$ Hence, $(3x-2)(2x^2-4x+3)=6x^3-16x^2+17x-6$
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