## Intermediate Algebra for College Students (7th Edition)

$6x^3-16x^2+17x-6$
Simplify.$(3x-2)(2x^2-4x+3)$ Now, $=3x(2x^2-4x+3)-2(2x^2-4x+3)$ $=6x^3-12x^2+9x-4x^2+8x-6$ Hence, $(3x-2)(2x^2-4x+3)=6x^3-16x^2+17x-6$