Answer
$6x^3-16x^2+17x-6$
Work Step by Step
Simplify.$(3x-2)(2x^2-4x+3)$
Now,
$=3x(2x^2-4x+3)-2(2x^2-4x+3)$
$=6x^3-12x^2+9x-4x^2+8x-6$
Hence,
$(3x-2)(2x^2-4x+3)=6x^3-16x^2+17x-6$
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