## Intermediate Algebra for College Students (7th Edition)

$(x,y)=${$10000,5$}
Since, we have two equations $2 \log x=y+3$ and $\log x=y-1$ Thus, $2 (y-1)=y+3$ or, $y=5$ Now, $\log x=y-1$ or, $\log x=5-1 \implies 10^4=x$ and $x=10000$ Hence, $(x,y)=${$10000,5$}