Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.4 - The Parabola; Identifying Conic Sections - Exercise Set - Page 802: 119

Answer

$x=${$2,4$}

Work Step by Step

Since, we have $x^2=2(3x-9)+10$ This can be written as: $x^2=6x-18+10$ or, $x^2=6x-8$ or, $x^2-6x+8=0$ Factorzie it. we have $(x-2)(x-4)=0$ Hence, solution set : $x=${$2,4$}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.