Answer
$x=${$-3,-1$}
Work Step by Step
Given: $(x+1)^2+(x+3)^2=4$
or, $x^2+2x+1+x^2+6x+9-4=0$
or, $2x^2+8x+6=0$
or, $x^2+4x+3=0$
or, $(x+1)(x+3)=0$
Hence, solution set $x=${$-3,-1$}
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 10 - Section 10.4 - The Parabola; Identifying Conic Sections - Exercise Set - Page 802: 116
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
