Answer
See the explanation below.
Work Step by Step
Standard form of a parabola is $x=a(y-k)^2+h$ and
Here, vertex:$(h,k)$
As we are given that two equations of a parabola
$x=4y^2$ and $x=4(y-1)^2+2$
Compare both the equations with standard form ,we have
vertex:$(0,0)$ and vertex:$(2,1) $