#### Answer

See the explanation below.

#### Work Step by Step

Standard form of a parabola is $x=a(y-k)^2+h$ and
Here, vertex:$(h,k) or (k,h) $
In order to get the vertex we will have to arrange the equation in the standard form of a parabola, for this need to complete the square for $y^2$.
For example:
Since we are given $x=-2y^2+4y+6$
It can be written as:
$x=-2y^2+4y+6$
or, $x=-2(y^2-2y+1)+6+2$
or, $x=-2(y-1)^2+8$ ; complete the square for $y^2$
Compare the given equation with the standard form.
Thus, vertex: $(8,1)$