Answer
vertex:$(-2,1)$ and defines at opens towards left.
and Domain is: $(- \infty, -2]$ and range is: $(-\infty, \infty)$
Work Step by Step
Since, we have $x=-3(y-1)^2-2$
Standard form of a horizontal parabola is $x=a(y-k)^2+h$
Here, vertex:$(h,k)$
Compare the above equation with the standard form.
Thus, we have vertex:$(-2,1)$ and defines at opens towards left.
and Domain is: $(- \infty, -2]$ and range is: $(-\infty, \infty)$