Answer
vertex:$(3,1)$ and defines at opens towards left.
and Domain is: $(- \infty, 3]$ and range is: $(-\infty, \infty)$
Work Step by Step
Since, we have $x=-4(y-1)^2+3$
Standard form of a horizontal parabola is $x=a(y-k)^2+h$
Here, vertex:$(h,k)$
Compare the above equation with the standard form.
Thus, we have vertex:$(3,1)$ and defines at opens towards left.
and Domain is: $(- \infty, 3]$ and range is: $(-\infty, \infty)$
