## Intermediate Algebra for College Students (7th Edition)

$x=-1$
Simplify $\dfrac{2}{x+2}+\dfrac{4}{x-2}=\dfrac{x-1}{x^2-4}$ Thus, $\dfrac{2}{x+2}+\dfrac{4}{x-2}=\dfrac{x-1}{(x+2)(x-2)}$ or, $2(x-2)+4(x+2)=(x-1)(1)$ or, $2x-4+4x+8=x-1$ or,$5x =-5$ Hence, $x=-1$