Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.2 - The Ellipse - Exercise Set - Page 780: 69



Work Step by Step

Simplify $\dfrac{2}{x+2}+\dfrac{4}{x-2}=\dfrac{x-1}{x^2-4}$ Thus, $\dfrac{2}{x+2}+\dfrac{4}{x-2}=\dfrac{x-1}{(x+2)(x-2)}$ or, $2(x-2)+4(x+2)=(x-1)(1)$ or, $2x-4+4x+8=x-1$ or,$5x =-5$ Hence, $x=-1$
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