Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Section 10.2 - The Ellipse - Exercise Set - Page 780: 68

Answer

$2xy^2 \sqrt [3] {5xy}$

Work Step by Step

Simplify $\sqrt [3] {40x^4 y^7}$ $\sqrt [3] {40x^4 y^7}=\sqrt [3]{(8x^3 y^6) (5xy)}= \sqrt [3] {8x^3 y^6} \sqrt [3] {5xy}$ or, $=2xy^2 \sqrt [3] {5xy}$
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