Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 816: 8

Answer

Radius:$r=3$ and center: $(a,b)=(-2,3)$

Work Step by Step

Use standard form of equation of circles; $(x-a)^2+(y-b)^2=r^2$ Here, $r$ defines radius and $(a,b)$ defines center. Then, $(x-(-2))^2+(y-3)^2=(3)^2$ Thus, on comparing the above equation with the standard form, we have Radius:$r=3$ and center: $(a,b)=(-2,3)$
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